(2/x)+(1/(x+1))=(5/(x^2+x))

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Solution for (2/x)+(1/(x+1))=(5/(x^2+x)) equation: 


D( x )

x = 0

x^2+x = 0

x+1 = 0

x = 0

x = 0

x^2+x = 0

x^2+x = 0

x^2+x = 0

DELTA = 1^2-(0*1*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-1)/(1*2) or x = (-1^(1/2)-1)/(1*2)

x = 0 or x = -1

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:0) U (0:+oo)

1/(x+1)+2/x = 5/(x^2+x) // - 5/(x^2+x)

1/(x+1)-(5/(x^2+x))+2/x = 0

1/(x+1)-5*(x^2+x)^-1+2/x = 0

1/(x+1)-5/(x^2+x)+2/x = 0

x^2+x = 0

x^2+x = 0

x*(x+1) = 0

x+1 = 0 // - 1

x = -1

x*(x+1) = 0

1/(x+1)-5/(x*(x+1))+2/x = 0

(1*x)/(x*(x+1))-5/(x*(x+1))+(2*(x+1))/(x*(x+1)) = 0

2*(x+1)+1*x-5 = 0

x+2*x-5+2 = 0

3*x-3 = 0

(3*x-3)/(x*(x+1)) = 0

(3*x-3)/(x*(x+1)) = 0 // * x*(x+1)

3*x-3 = 0

3*x-3 = 0 // + 3

3*x = 3 // : 3

x = 3/3

x = 1

x = 1

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